I don't know what the equation is, but going to my original question, are you saying that the hob and oven can be wired into the same place?
Thanks!
Pask
The thing about cookers is that they don't run flat out at maximum power all of the time - in fact often never. Think how many times you put a large pan of cold water on each ring and turn them all on at once along with the oven.
So traditionally the assumed loading for a cooker is 10A + 30% of the remainder of the full load current.
In your case you have a 9.6kW load, i.e. 42A, so the load the circuit has to support is 32 x 0.3 + 10 = 19.6A. And you're supposed to add 5A if the cooker switch has a socket. But basically your hob+oven is viewed as a 19.6A load, not a 42A one.
How valid is this? YPYMAYTYC. I'm not a big fan, because people are more adventurous with cooking these days and use cookers more extensively than when that diversity guideline was worked out (probably not long after WW II), and induction hobs complicate things because they can have a boost function whereby if you aren't using all of the zones the others can get more power, which does affect the validity of a calculation which assumes you won't have everything going flat out very often or for long.
That said, there is a
lot of headroom between 19.6A and 40A - even with an induction hob you would be on solid-as-a-rock ground to say that the design load for the circuit is no more than 40A.
So - what would happen if you turned every knob up to 11?
SFA. A 40A breaker will let 45A through indefinitely - a fact which anybody who thinks they are justified in calling themselves an electrician ought to know.