I currently have fluorescent tube lights under 2 kitchen wall cabinets (on the same wall separated by the cooker in the middle). Both sets of tubes plus the cooker hood extractor fan and light are powered from a switched, fused spur mounted on the wall. As far as I can tell the fused spur wiring terminates on top of one of the wall cabinets just below the ceiling into a choc block inside a plastic box where its distributes 3 ways, to the cooker hood and down to both sets of tube lights. The tube lights have their own switches integrated in which we use to turn them on and off.
The tubes apparently are an odd size so finding replacements is expensive, I would like to replace these with LED strips. I have bought a roll of 5 metres which will be cut in 2 and stuck under the cabinets and an LED driver http://amzn.eu/dNhNvxb to power them which will be placed on top of the cabinet and powered from the distribution block. The existing 2 core wiring currently powering the tubes will be wired into the DC side of the driver instead.
My question is how can I independently turn the LED strips on and off without using the switch on the fused spur as sometimes it would be nice to use the extractor fan without turning on all the lights? I have read that it is unwise to have the LED driver powered on permanently.
The tubes apparently are an odd size so finding replacements is expensive, I would like to replace these with LED strips. I have bought a roll of 5 metres which will be cut in 2 and stuck under the cabinets and an LED driver http://amzn.eu/dNhNvxb to power them which will be placed on top of the cabinet and powered from the distribution block. The existing 2 core wiring currently powering the tubes will be wired into the DC side of the driver instead.
My question is how can I independently turn the LED strips on and off without using the switch on the fused spur as sometimes it would be nice to use the extractor fan without turning on all the lights? I have read that it is unwise to have the LED driver powered on permanently.