star/delta line current formulas

right i haven't calculated any thing like this for ages and cant remember how to do it so if any one could let me know id be grateful


ps im british living in Australia so no jokes about the rugby

Whew, time to dust off the old textbook and double check the finer points. Assuming a balanced system:

The current in one leg of your star is equal to the current in two legs of your delta.
I(an) = I(ab) + I(ac)

The line to neutral voltage of your star is equal to the line to line voltage of your delta divided by the square root of three and phase shifted -30 degrees.
V(an) = V(ab)/sqrt(3) and phase shifted -30º

The impedance in your star is equal to the impedance in your delta divided by three.
Z(star) = Z(delta)/3

I apologize for the American standard notation. Do you call your phases R, S, and T instead of A, B, and C?

three phases L1, L2, L3 or red yellow blue in england havent found out what there called in AU yet

wow thats a lot to take in but thanks