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A. `60//77 ms^(-2)`B. `80//77 ms^(-2)`C. `180//77 ms^(-2)`D. `60//77 ms^(-2)`

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CSolution :

From constraint relation , we can see that <br> `2TX_(B)=2TX_(A)` <br> `X_(A)=3/2 X_(B) implies a_(A) =3/2 a_(B)` <br> So let `a_(B)=a` then `a_(A)=1.5a` <br> Writing equation of motion : <br> From block A, <br> `2T=70a_(A)=105a = 3 xx 35 a ` <br> `35a = 2/3 T`..(i) <br> From block B, <br> `300-3T=35a_(B)=35a` ..(ii) <br> solving eqs. (i) and (ii) we get <br> `300-3T=(2T)/(3) implies 900-9T=2T implies 900 = 11T` <br> `T=(900)/(11)N` <br> `a_(A)=(180)/(77)ms^(-2) and a_(B) = (120)/(77)ms^(2)`.