I am familiar with how looping in at the switch on a lighting circuit works, i.e. all three neutrals connected together, all three earths connected together, live in and out in com and live to light in L1. But in a double switch how is this done. There will be an in and an out and two light cables. Is it all four neutrals connected together, all earths connected. The light lives will still be in the two L1s, but what about the live ins and outs. Does one go in each com and a bridging wire put in, which I believe would work.
Loop in at Switch for Double Switches
- Thread starter Barnman
- Start date
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yes
If you didn't, what do you think would happen?
Bonus Q:
You have a 3-gang 2-way switch:
3 lighting circuits looping through it, each switch is controlling 2 lights, and how/where they are located means that each one has its own cable from the switch.
How many conductors will there be at the switch, and how deep a back box will you need to get them all in?
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Not even closeAnswer - 11 Earths, 8 Neutrals, 10 Lives (including two jumpers), 9 wires in the three core. So 27 plus earths. As deep as possible back box.
Yup, and 48 with 2-way.
3 lighting circuits looping through - each with 3 conductors on the loop in, 3 on the loop out (6x3 = 18)
Each switch feeding 2 lights - 3 switches x 2 lights = 6 cables x 3 cores each = 18
18 + 18 = 36
plus if two way switching in the conversion method would add a further 3 cables with 4 conductors each = 12 +36 = 48
PS - back box required would be a 47mm - not only for depth but for the knock out sizes too!
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