Dear All,
I have a shower extractor fan which is connected to my upstairs lighting supply and operated via a switch on the landing. The fan has a timer overrun facility. Isolation of the extrator fan is via a fan isolator switch.
My shower pump is currently plugged into a socket which forms part of the upstairs ring circuit. I turn the switch on the socket off during the day to ensure that if there are any leaks 'downstream' of the pump that the puimp does not operate.
Can anyone advise if I can remove the socket which feeds the pump from the upstairs ring and connect it to the extractor fan isolator switch. This would mean that the shower pump is only switched on when the fan switch on the landing is on.
Many thanks
paul
I have a shower extractor fan which is connected to my upstairs lighting supply and operated via a switch on the landing. The fan has a timer overrun facility. Isolation of the extrator fan is via a fan isolator switch.
My shower pump is currently plugged into a socket which forms part of the upstairs ring circuit. I turn the switch on the socket off during the day to ensure that if there are any leaks 'downstream' of the pump that the puimp does not operate.
Can anyone advise if I can remove the socket which feeds the pump from the upstairs ring and connect it to the extractor fan isolator switch. This would mean that the shower pump is only switched on when the fan switch on the landing is on.
Many thanks
paul