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Why is it meaningless? Other people have already said they check the temperature rise when testing out a boiler. It's a good indication of boiler performance. You don't even know how to convert m³ to kw so I'm not sure how you're going to get 'started'

The man with the ironic name is back!

You were really struggling to understand the theory of the temperature differential. I'm still not sure if you understand it.

That's probably better than making a fool out of yourself again (n)

It's all gone quiet :mrgreen:

Like calling me a bellend for example? I see your comment got deleted I was looking to compare my results to what other people had seen but it appears no one knows how to work it out so no one can give me an answer. If you can't convert m³ to kw I don't think you've got much hope. Playing...

I realise that now. I was thinking m³/hr equates to kwh but it's actually kw.

The 'Gaswizard' has also missed out the correction factor. Are you an RGI Gaswizard?

My gas rate is 2.364 m³/hr which is slightly lower than the specified 2.5 m³/hr. Vaillant do use quite a low kw/m³ figure of 10.43 kw/m³ to work out the nominal gas rate though. My gas supply is actually 11.14 kw/m³ so I would expect it to be a bit lower.

You're talking rubbish now. What would be the point in me shadowing you? It's clear I wouldn't learn a lot.

Calls himself 'Gaswizard' can't even convert m³ to kw :mrgreen:

I posted a perfectly reasonable question but all the idiots came out of the woodwork. It's been a quiet day at work so you've kept me amused. Thanks for that (y) It's not wrong. You're just an idiot. Tell me what it should be then :mrgreen:

Neither do I. It's on my gas bill (y)

OK then what should it be? Intelligent? Working out kwh from m³ is pretty simple. I reckon even you could manage it.

Nozzle The calorific value on my bill is stated as 39.2 so 2.5 m³/hr equates to 27.84 Kw.

Why does the formula not use gas rate then? Look on the bright side at least you learnt something today (y) You like to think you're God's gift to RGI's but you're clearly not. Bellend? Pot, kettle, black? I'm only interested in the output. The input is obviously higher than 23 KW. 2.5...

I'm talking about calculating temperature rises (y)

To work out the 35 degree rise or any rise you use the following formula: KW rating of boiler ÷ 35 degrees (or which ever temp rise you want to work out) ÷ specific heat capacity of water = flow in kg/s You then multiply kg/s by 60 to give l/min Just to prove the point I'll work it out for 4...

You can work it out accurately like i have though. It's not difficult.