H
holmslaw
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Er, the current imbalance is caused by a lower value in the neutral than in the live, at the RCD.So if you join neutral to earth through a very small resistance it is easy for between 15 and 30 mA or more to flow from neutral (and not in the live), ie enough to trip the RCD.
It appears that I "have to" do no such thing.you'll have to explain
Wow! Where did you get that from? It's a difference between line and neutral - any difference over 15-30A. Do you know how an RCD works?Er, the current imbalance is caused by a lower value in the neutral than in the live, at the RCD.
In the context of this topic, more current is flowing in the live than in the neutral, whereas you said that "it is easy for between 15 and 30 mA or more to flow from neutral (and not in the live), ie enough to trip the RCD".It's a difference between line and neutral - any difference over 15-30A.
While I'm here, it would probably help any novices reading this if you'd stick to using either "line" or "live" when referring to the phase conductor, instead of flicking between the two terms.
OK. So we're both correct.BS3036's comment was based on the individual circuit at the fault, whereas yours is based on the RCD feeding all the circuits..
both are correct..
Who are you, BS3036?Who are you, a policeman?While I'm here, it would probably help any novices reading this if you'd stick to using either "line" or "live" when referring to the phase conductor, instead of flicking between the two terms.BS3036 said:live/line/live
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