Hmmm did you produce the goods ? Certainly did not elaborate.
The attachment looks right, triple spike crown at each orifice.
I reckon the volume shown is correct, however or whoever produced it or at least we have made the same mistakes !!
So I recalculated using 5 mm radius for the cylindrical hole (I had previously used the original 10 mm rad)
Edit : Had written wrong figure for pyramid base area reposted edit. I then realised I had miscalced the volume of pyramid edit no.2
!
1) Pyramid at one corner = base area 32.476 mm² Height 3.535 mm. Volume 38.273 mm³ x 2 = 76.546 mm³ = vol of two pyramids.
2) Length between diametrically opposite corners of cube √(100² + 100² + 100²) = 173.205 mm Less two pyramid heights 173.205 - (2 x 3.535) = 166.135 mm
3) My 10 mm diam cylinder including fresh air pockets has volume of π5² x 166.135 = 13048.212 mm³ Add the two pyramid vols. 13048.212 mm³ + 76.546 mm³ = 13124.758 mm³
4) Calced one cylindrical wedge (the fresh air cut) Depth at wide end 2.5 mm Height of wedge 3.5355 mm angle 35.2644° (I used
https://planetcalc.com/1442/) 22.2598 mm³. 6 x 22.2598 = 133.559 mm³
5) 13124.758 mm³ - 133.559 mm³ =
12991.2 mm³ total material removed, Being 12991.2 ÷ 1000 000 = 0.01299 Or approximately 1.3 %
So mm666 suggests in his result a Volume = 987009.09 mm³ I imagine mm666 means that is the material left in the processed cube.
So this suggests 12990.91 mm³ removed.
magicmushroom666 cad offering matched by my calculation, reckon 'tis correct !!
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