Ok let's lighten this forum up a bit

Explained another way......

The ISS (and its occupants) are falling to earth.
They are also traveling at around 5 miles per second over the Earth.
In that second, the curve of the Earth means that its surface has "fallen" another five miles away from the ISS.
The ISS is constantly falling towards Earth, but the Earth is constantly falling away from the ISS.

I think ;)
 
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If anybody wants to calculate it, the formula is:

Fgravity = G m1m2 ÷ r2

Where big G is a constant = 6.67 x 10-11 Nm2/kg22 gravitation constant is force pull between 2 bodies

r is distance from centre of earth to person on space station (410kms ish).

m1 mass of earth
m2 mass of person.
 
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Do you want to calculate the gravitational pull between you and the squirrel........

It brightend my day up and I felt sharing it with you lot would brighten everyone else's evening up.
 
Explained another way......

The ISS (and its occupants) are falling to earth.
They are also traveling at around 5 miles per second over the Earth.
In that second, the curve of the Earth means that its surface has "fallen" another five miles away from the ISS.
The ISS is constantly falling towards Earth, but the Earth is constantly falling away from the ISS.

I think ;)

A fair explanation.
 
If anybody wants to calculate it, the formula is:

Fgravity = G m1m2 ÷ r2

Where big G is a constant = 6.67 x 10-11 Nm2/kg22 gravitation constant is force pull between 2 bodies

r is distance from centre of earth to person on space station (410kms ish).

m1 mass of earth
m2 mass of person.

Believe it's little g, universal gravitational constant, Big G is what we experience on earth.... I think?
 
how was this supposed to lighten up my day? I'm now more confused than normal.
 
how was this supposed to lighten up my day? I'm now more confused than normal.

ok, make it simple imagine you're on planet earth and you're in an infinitely long free falling lift, you could float around as if you're weightless but of course you aren't.
 
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