Pls help me find a replacement 9v adapter

[ey143]

Hi

I need to find a similar adapter that can handle the power rating of my existing one as shown in the picture attached. It is used to charge a wireless foot peddle for a clinic. Someone broke the end connector pin as shown.

If I’m correct I cannot use this one from Amazon because it has a negative centre polarity pin?

https://amzn.eu/d/06EfToqP

If the ampage is 2A what is meant by the numbers after the 50-60 Hz ie 0.5A (0.5-0.2A)?

 

[FrodoOne]

I need to find a similar adapter that can handle the power rating of my existing one as shown in the picture attached. It is used to charge a wireless foot peddle for a clinic. Someone broke the end connector pin as shown.

If you have the skill (or know anyone who has) you could just replace the connector.

You will need to check if it is 2.5 mm (which is probable)
or
2,.1 mm !!!!

If I’m correct I cannot use this one from Amazon because it has a negative centre polarity pin?

https://amzn.eu/d/06EfToqP

A badly worded Amazon "Blurb" (which is NOT unusual)
but
it says

"Negative Sleeve Positive Polarity"​

which (probably) means that the Sleeve is Negative and the Centre is Positive. (Which is "usual".)

However, it is rated at only 1 A and you may need more,
since the original was rated at 2 A

If the ampage is 2A what is meant by the numbers after the 50-60 Hz ie 0.5A (0.5-0.2A)?

That is the "Input" AC current
(At a low AC input voltage [100 V] the input current will be higher,
At a high AC input voltage [240 V], the input current will be lower.)

The "Output" 9 V DC current should be up to (at least) 2 A

 

[Sureitsoff?]

You could buy one from here

https://www.digikey.com/en/products/detail/sl-power-advanced-energy/ME20A0903F01/5400147

that shows an American site but there is a British one

or

Pardon our interruption...

 

[FrodoOne]

You could buy one from here

Pardon our interruption...

Which seems to be somewhat "overpriced" - in my opinion.

Much cheaper to replace the connector.

 

[Sureitsoff?]

I agree cheaper to replace the connector (wheres Maplin when you need them.....) but if you cant find someone to replace it for you if you dont have the skill then buying a new one might be easier and it it is in a medical enviroment a new one might be better

 

[FrodoOne]

I agree cheaper to replace the connector (wheres Maplin when you need them.....) but if you cant find someone to replace it for you if you dont have the skill then buying a new one might be easier and it it is in a medical enviroment a new one might be better

Since "It is used to charge a wireless foot peddle for a clinic. " (Post #1)
the "medical environment" specification may not be of any importance.

 

[jj4091]

You could perhaps split the shroud with a stanly knife and resolder the wires then glue back together with super glue and tape for mechanical strength. Or https://cpc.farnell.com/pro-elec/pe...4605&s_kwcid=AL!5616!3!426684131180!!!network}!2170600276936!&gad_source=1&gad_campaignid=9262013734&gclid=CjwKCAiAzZ_NBhAEEiwAMtqKyyU-ekrB_WhcWBf64H8MStNmv6iBTT_l7DvYmOQmGsTpzDfACY7eEBoCnOYQAvD_BwE

 

[ey143]

https://amzn.eu/d/0hcBpTJC

So I bought this adapter from Amazon it seem to work fine with the foot peddle and charge it ok.

My question is why if they can make an adapter like this, then why make the original one as a block with detachable kettle lead cable?

 

[jj4091]

Bump the price and profit up. Although perhaps wall warts weren't available when it was designed.

 

[ey143]

Wall warts?

The foot peddle is only a year or two old. I was assuming there is a technical reason why those bulky power supplies are made if they cannot just to the plug alone like the new one?

 

[jj4091]

Sentence 1 then.

 

[Why Not Indeed]

why make the original one as a block with detachable kettle lead cable?

Why not? It's more flexible - will work in any country with appropriate local cable.
Perhaps the original product is better specced than the replacement you've bought.