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What you've done is unlikely to have made any difference to your original problem. Have you tried cleaning the pump impeller, as Johntheo5 and I suggested?

You can say that again! :giggle:

That's what I was getting at, the starting point isn't quite clear

Assuming the level was higher than that before you did it, it shows the cold feed pipe isn't blocked

Yes, that's fine, and has the advantage you can tip the drained water back in the F/E tank, saves wasting any inhibitor.

No, from the system, eg one of the drain points, usually near a rad. Ideally get somebody in the loft to check the level in the F/E tank falls as water is drained off. Better than just listening for it

But the impeller can get clogged with crud, reducing the output. That's what happened with mine .

Agreed, and the other European monarchies cost a fraction of ours

King Bill V. King Bill IV was the one just before Victoria

As the problem is the same on CH and HW, my money is on it being a pump problem. Similar thread https://www.diynot.com/diy/threads/boiler-kettling-periodically.651739/post-6136047 not long ago

You could have just throttled the existing rad

And check that the rad iso valve (on the other end of the rad from the TRV) is fully open

OK, got it!

Just curious - what's beautiful about it?

Cripple vans, I remember

Not exactly nativity style is it? :giggle:

Good point, and plugwash's comment. Am I right thinking the induction hob works by creating eddy currents in the pan, hence resistive heating? It would be interesting to know how the current varies with voltage

Thinking about it a bit more - with a pure inductance (or capacitance) the impedance is constant at a given frequency, so the current varies directly with voltage. I'd guess that applies to an induction hob but not 100% sure.

As was discussed on here a while back, with an electric motor (normal induction type) with varying voltage the power stays very nearly constant so the current varies inversely

That's wrong! It should be l/s = kW/4.18/DT, l/h = 3600*kW/4.18/DT = 860*kW/DT, lpm = 860/60*kW/DT, as John said. Worrying that Danfoss forgot to correct from second to hour, will somebody tell them?