Fair enough - with those numbers/assumptions I would agree. In fact, I think the disconnection time of a B32 at 100A is nearer to 25 seconds than to 12 seconds, so we could be talking nearer to 2,500 times the energy.What I am saying is with a B32 MCB the current needs to be 160A to trip in 0.01 of a second and unless the earth loop impedance is below 1.44 ohms it will not trip on the magnetic part of the trip ... So likely with a B6 MCB 100A will flow for 0.01 of a second but with a B32 MCB it will flow for 12 seconds before disconnecting. That's 1200 times the energy which will need dissipating as heat to that using a B6 MCB.
However, that's because you have assumed a fault current of 100A - i.e. 'a fault loop impedance' (Zs+fault impedance) of about 2.3 Ω (at 230V). If the fault current was nearer to (or equal to or greater than) 160A, then the disconnection time, hence energy involved, would be much the same with a B6 and B32.
However, you raise an interesting point. As I said at the start of my post, it seems that many electricians would say that that the MCB was there only to protect the cable, not accessories or loads (so would be 'happy' provided that a B32 was affording adequate fault protection the the cable, which it probably would) - but you are thinking of 'protection' of the lamp/fittings fed by the cable (i.e. to prevent the welding you experienced). As you will be aware from my mutterings, I have always felt that it is very reasonable to use the lowest possible rated OPD to 'protect' a low current load (many of which don't have much/any internal protection), even if a much higher-rated one would be adequate to protect the cable (e.g. I often use 1A fuses in plugs for small electronic things) - but it seems that many electricians stick to their view that the OPD needs only to protect the cable.
Kind Regards, John
