H
holmslaw
..
Actually, no. Maximum power can only be drawn when the load impedance matches the battery's impedance. Even then, half the energy is wasted. The rated current I think is 250A and that will be at something less than 12V, so less than 3kW (maybe 2kW).Or 3Mw for 0.288 seconds
Note the
I'm pretty sure if you connected a 3kw load to that dinky toy, all you would get would be a puff of smoke followed by deathly silence.
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