C chapeau Joined 2 Oct 2007 Messages 2,280 Reaction score 200 Country 7 Sep 2012 #31 it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero.
it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero.
C calorific 7 Sep 2012 #32 chapeau said: it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero. Click to expand... Yes, a zero divided by zero.
chapeau said: it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero. Click to expand... Yes, a zero divided by zero.
S Sombrero 7 Sep 2012 #33 chapeau said: it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero. Click to expand... it works with letters becuase thats algerba. So are you saying the formula works unles x and y = 1?
chapeau said: it works when you use two different letters. If you substitute 1 for x and y then you get a divide by zero. Click to expand... it works with letters becuase thats algerba. So are you saying the formula works unles x and y = 1?
S StephenW Joined 9 Jul 2009 Messages 272 Reaction score 42 Location Buckinghamshire Country 11 Sep 2012 #34 diynoob's formula begins with the phrase For 2 non zero numbers x and y such that: x = y Click to expand... So, if x=y then (x-y) must be zero. So the phrase (x+y)(x-y)=y(x-y) just proves that 0=0 and you can't divide by (x-y) if x and y have the same value.
diynoob's formula begins with the phrase For 2 non zero numbers x and y such that: x = y Click to expand... So, if x=y then (x-y) must be zero. So the phrase (x+y)(x-y)=y(x-y) just proves that 0=0 and you can't divide by (x-y) if x and y have the same value.
D diynoob Joined 21 Jan 2004 Messages 300 Reaction score 17 Country 11 Sep 2012 #35 Yep, diving by (x-y) is the flaw in the 'proof'.
E EddieM 16 Sep 2012 #36 EddieM said: is this bit right?? (x+y)(x-y)=y(x-y) Dividing by (x-y) gives: x + y = y Click to expand... no its not that, surely the alegbra is wrong :- dividing by (x-y) doesn't give x + y = y does it?? my maths is horribly out of date.
EddieM said: is this bit right?? (x+y)(x-y)=y(x-y) Dividing by (x-y) gives: x + y = y Click to expand... no its not that, surely the alegbra is wrong :- dividing by (x-y) doesn't give x + y = y does it?? my maths is horribly out of date.
pred Joined 2 Feb 2011 Messages 4,785 Reaction score 561 Location Bristol Country 16 Sep 2012 #37 UriBentMySpoon said: Wow the one person I tought would bite hasn't. Perhaps everyone else being humourously contrairy have unwittingly used up his arguments before he got to them. Click to expand... Perhaps the 1 person you "tought" or thought would bite is maybe having difficulty adding 1+1, or he may have a "flat bat" syndrome in his calculator.
UriBentMySpoon said: Wow the one person I tought would bite hasn't. Perhaps everyone else being humourously contrairy have unwittingly used up his arguments before he got to them. Click to expand... Perhaps the 1 person you "tought" or thought would bite is maybe having difficulty adding 1+1, or he may have a "flat bat" syndrome in his calculator.
F FiremanT Joined 16 Jan 2012 Messages 10,560 Reaction score 2,350 Location Uk Country 18 Sep 2012 #38 mitch66 said: UriBentMySpoon said: The next step is to tell me I have actually got my question wrong and state theat your answer is correct to the question I should have asked. Click to expand... Not if the wheels can't go faster than the conveyor. Click to expand... Or if no one is there to see it
mitch66 said: UriBentMySpoon said: The next step is to tell me I have actually got my question wrong and state theat your answer is correct to the question I should have asked. Click to expand... Not if the wheels can't go faster than the conveyor. Click to expand... Or if no one is there to see it