Quite a few questions here, any help would be great
Have I got this right
Short circuit fault between phase and neutral causes a massive in rush of current which activates the protective device. This is a fault between R1 and Rn and has nothing to do with R2 i.e. does not involve the CPC of the circuit and the earthing conductor or the earth fault loop path. So the fault is dealt with at the CU. PSSC.
Now a phase earth fault will send the fault current from the origin of the fault down the CPC, through the earthing conductor, back to the transformers earth then back down the phase conductor from the transformer through the supply fuse to the protective device, which breaks the circuit. PEFC
Now if this earth fault is on a TT system, there is no physical connection to the transformer, no conductor. The electricity finds its way back to the transformer via the actual ground we stand on.
That is what I am finding hard to understand. I would have thought the electricity would just be absorbed I guess, be nothing left by the time it got to the transformer, or just shoot off in all directions.
What are the shock implications for people standing near the Earthing rod, or is it straight away at earth potential, which if it is how has it got the energy to get back
The transformer I guess could be quite some distance away (what sort of distance could be involved?)
So there must be more resistance to electricity in that little bit of basic insulation (>200Mohms) around the conductors than in say 200 meters of earth (fault to transformer) where 200ohms is considered unstable. ??
Hence RCD protection
Neutral to earth fault not sure what happens there.
Thanks
Have I got this right
Short circuit fault between phase and neutral causes a massive in rush of current which activates the protective device. This is a fault between R1 and Rn and has nothing to do with R2 i.e. does not involve the CPC of the circuit and the earthing conductor or the earth fault loop path. So the fault is dealt with at the CU. PSSC.
Now a phase earth fault will send the fault current from the origin of the fault down the CPC, through the earthing conductor, back to the transformers earth then back down the phase conductor from the transformer through the supply fuse to the protective device, which breaks the circuit. PEFC
Now if this earth fault is on a TT system, there is no physical connection to the transformer, no conductor. The electricity finds its way back to the transformer via the actual ground we stand on.
That is what I am finding hard to understand. I would have thought the electricity would just be absorbed I guess, be nothing left by the time it got to the transformer, or just shoot off in all directions.
What are the shock implications for people standing near the Earthing rod, or is it straight away at earth potential, which if it is how has it got the energy to get back
The transformer I guess could be quite some distance away (what sort of distance could be involved?)
So there must be more resistance to electricity in that little bit of basic insulation (>200Mohms) around the conductors than in say 200 meters of earth (fault to transformer) where 200ohms is considered unstable. ??
Hence RCD protection
Neutral to earth fault not sure what happens there.
Thanks