No argument about that - it is certainly 'what it means'.Why not ? If the cable is indeed uniform, then that is exactly what it means - regardless of how difficult it might be to measure.However, it does lead to some conclusions which I find rather hard to believe. Can you really believe that, say, the IR of 1m length of this cable really is >2TΩ (i.e. >2,000,000 MΩ?
Yes, they are difficult numbers to get one's head around, but that was not the basis of my statement. I did some mental arithmetic based on guesstimates, which resulted in my 'finding the figure hard to believe'. However, I've now done some 'scribbling arithmetic' which indicates that my mental attempt was seemingly appreciably wrong ....I think the only problem is a mental one - in that (in this context) there is a general attitude of "> xG == unmeasurable ≈ infinite" .... I think it's just a mental hangup from dealing with "numbers we can't get our head round".
The resistivity of PVC is around 10^15 Ω.cm. Per spec, the conductor diameter of Cat5e is about 0.5mm and the insulation thickness about 0.25mm, hence a totl 'insulated conductor diameter' is about 1mm. The very difficult thing is guessing the width of the area of contact (when everything is squashed together) between two of the insulated conductors, but I have wildly guessed at 0.5mm - which equates to a contact area of 5cm² for a 1 metre length. With an insulation thickness of 0.25mm that all works out at a resistance of about 5 TΩ (for 1 metre of cable). That's certainly compatible with, and in the same ballpark as, the figure calculated above (from the posted spec) of ">2 TΩ" ... so I have to concede that I probably should not have "found it hard to believe"!
Kind Regards, John