Indeed - as I've just said. The figures for flex are, indeed, weird, and maybe reflect 'usage' (mechanical stresses), which probably has more impact as the cable gets smaller - so I'm ignoring them!
I'm on the case - watch this space!
A power law curve (with a power of 0.6077) fits the Table 4D5 Method C CCCs (1mm² - 16mm²) almost perfectly - see graph (line is power curve, red points are 4D5 figures) and tabulation. So, if we go with extrapolation based on that power curve, the answer to BAS's question is that 7 separate 0.57mm² conductors in parallel probably have a total CCC of around 78.4A (7 x 11.2A), as compared with 37A for a 4mm² conductor.
I probably should have added that, in practice, it would not be very practical to exploit this. To get that 78A CCC would require the 7 separate 0.57mm² conductors to be appreciably physically separated. If they were 'grouped' together, the consequent de-rating factor would get one back to much closer to the 4mm² CCC - which I suppose makes sense.
Quite so - the OP got his answer (plus a hint at a 'pragmatic variant'!) early on. It was the OP that raised the question about using connectors in parallel because of 'surface area' considerations, which the OP thought was something which applied to conductors in general.
You're welcome. As I recently wrote, you really got the answer you wanted/needed very quickly, and within the first two or three replies. The rest can be put down to 'wider curiosity/education'
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