A question for Vibrobullit/elrobbo/alovecollege etc etc

[starspark]

For vibro first only please then im sure every1 will answer if he cant!!!

A light bulb is rated at 250watts at 110volts.
Its connected to a 230volt supply.
What power will the light bulb use at 230volt?

Shall i give you five minutes??

 

[starspark]

right thats 10 minutes so.....
I have every confidence you will find it somewhere in your regs book library!!!

 

[vibrobullit407]

For vibro first only please then im sure every1 will answer if he cant!!!

A light bulb is rated at 250watts at 110volts.
Its connected to a 230volt supply.
What power will the light bulb use at 230volt?

Shall i give you five minutes??

250 / 110 = 2.27A

110 / 2.27 = 48.5ohms

so
230 / 48.5 = 4.74A

230 x 4.74 = 1.09 KW

 

[starspark]

Sorry but it is now clear if you knew the answer and formula/s it would have been answered by now so even if you do answer correct i will only believe some1 has told you or you have found the answer somewhere.

 

[RMS]

For vibro first only please then im sure every1 will answer if he cant!!!

A light bulb is rated at 250watts at 110volts.
Its connected to a 230volt supply.
What power will the light bulb use at 230volt?

Shall i give you five minutes??

250 / 110 = 2.27A

110 / 2.27 = 48.5ohms

so
230 / 48.5 = 4.74A

230 x 4.74 = 1.09 KW

Give yourself a gold star.

 

[echoes]

Went round the houses a bit though:

P proportional to V² [Assume R is constant.]

P = 250 x (230/110)² = 1.09 kW.

 

[vibrobullit407]

Well starspark right or wrong? I didn't bother putting the ohms law triangles up hope that's ok! Did I past your test? Will you now accept me and bury the hatchet as it is now becoming very tiresome!

 

[vibrobullit407]

Went round the houses a bit though:

P proportional to V² [Assume R is constant.]

P = 250 x (230/110)² = 1.09 kW.

Doesn't matter how you get there, it's getting there that matters!

 

[starspark]

Well done echoes very good!!!
Vibro, there is no way that would take twenty minutes to figure out if you knew it.

 

[JACKC]

It won't use any power as 230v across a 110v lamp will blow it up.
Simples

 

[starspark]

well yes that also smart arts!!

 

[vibrobullit407]

Well done echoes very good!!!
Vibro, there is no way that would take twenty minutes to figure out if you knew it.

I didn't take 20 mins. Its basic ohms law starspark. I answered your question when I saw your post! How do you think I got the answer? It's not who wants to be a millionaire is it! Have I won a million?

Here's a hint starspark W= IxV and V=IxR

not rocket science is it!

Nice to see that even when I answer your question correctly you still can't be thankful can you! I also like the way you congratulate some one else very mature!

 

[starspark]

posted 6.55 answered 7.13 which is 18mins rounded up 20 mins.
So it took twenty minutes?

I can tell echoes knew it as he knew how to do it in quickest form.
If you tell me who helped you with it ill thank them no problem!!

 

[starspark]

Here's a hint starspark W= IxV and V=IxR

On reflection at your post i definitely think you had help as you have just got that formula wrong!!!
Or at least the symbols!!
What is W do you mean watts??
Thats a unit measurement of power!! P?
So its P = IxV or P=(I2R)!!!
Oh dear i love it tripped yourself up all that good work getting help undone!!!
Like you said not rocket science is it!!!

 

[vibrobullit407]

posted 6.55 answered 7.13 which is 18mins rounded up 20 mins.
So it took twenty minutes?

I can tell echoes knew it as he knew how to do it in quickest form.
If you tell me who helped you with it ill thank them no problem!!

It never took me 20 mins it took me about a couple of mins. Just because you posted doesn't mean I saw it straight away does it!

Who would help me with this question? You are certainly looking like a bit of a c#@k when I easily answered your basic question. Just because you seem very lacking in electrical knowledge as I have pointed out in several threads. For gods sake you do not know that a regulation number in the BGB identifies which part and chapter it is from! I think you have shown yourself to be less than competent in this field so hopefully my suspicions are correct and you are not carrying out work in other peoples houses as you are a liability!