Sure, in Bernard's case we would have N=M. Per that Note, that means that the 'other cables' (of which there are none, N-M=0) can be de-rated on the basis of their being N-M (i.e. zero) of them. However, as I asked, the note appears to be silent about the derating of cables which are not 'others' (i.e. all M of them in Bernard's case) - so, if you take the wording of the note at face value, that silence would seem to imply that no 'relaxation of derating requirements' can be applied to them. However, that's so daft that it surely can't be what was intended?N = M?What do you think?
Are we perhaps all missing some other note or text which is saying that if none of the cables are carrying more than 30% of what would be their derated CCC, then no derating is required?
Kind Regards, John