95.05 % of the original volume remains.
Started with 1000 000 mm³, removed 49515.008 mm³, leaving 950484.992 mm³.
950484.992 ÷ 1000 000 = 0.95048'ish hence 95.048% of original volume remains.
At one corner of the cube.
Need to visualise the triangular based 'pyramid'.
Then the three odd shaped 'cylindrical wedges' a little like a tilted cylindrical tank having an open end with fluid just dribbling out, the fluid is in the shape of a cylindrical wedge.
In this case the wedges represent the fresh air being cut as the tool works its way into the cube, the curves slowly disappearing as the tool fully enters the cube.
So calc the pyramid vols, then the distance between the pyramid bases use this to calc a solid cylinder vol from which we subtract the six cyl' wedges, this being the material removed between the pyramids.
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