I believe it is called Archimedes Principle.
Eureka
I believe it is called Archimedes Principle.
And if you really want to waste a few brain cells, our favourite mad scientist puts a half-filled glass of water on the scales. He then dips his finger in it without touching any part of the glass (Don't ask why). Do the scales read more, less or the same?
You're both wrong.No you won't you will displace your own volume of water.You don't need to add the weight of the bather to the weight of water.
The bather will displace his own weight of water
... if the bath is filled to the overflow, and you get in, you will displace water which will go down the overflow or slop over the side....
...Ignoring, for now, the scenario of the bath overflowing,...
You're both wrong.No you won't you will displace your own volume of water.You don't need to add the weight of the bather to the weight of water.
The bather will displace his own weight of water
Ignoring, for now, the scenario of the bath overflowing, the volume of water displaced by a buoyant object has the same weight as the object. The bath is then supporting the weight of the water and the weight of the floating object.
Wrong, how can it not overflow? the bath is full.[/quote]Ignoring, for now, the scenario of the bath overflowing
more
by the weight of the volume of liquid that he has displaced with his prodder
the volume of water displaced by a buoyant object has the same weight as the object.
The question clearly stated a half-filled glass, and the finger not touching the glass. So, discounting a hugely fat finger, the glass cannot overflow.more
by the weight of the volume of liquid that he has displaced with his prodder
Wrong, indeed if the glass was full, and the resulting water displaced ran off the scales then the weight would go down.
There will always be gravitational pull.The fact that you have stuck you digit into a glass of water, has no effect as there is no additional force exerted onto the scales. weight of course being mass x acceleration. (there is no acceleration unless you cut you finger off).
So, if you had some sort of strain gauge on the crane, it would not change as the weight was lowered into the water? What if your 1000 t weight was the same density as water? What if your 1000 t weight was a boat?You could do the same with an olympic swimming pool and a 1000 tonne weight suspended from a crane, there would be no increase in weight of the swimming pool. (as long as the crane is not in the pool!)
Should it not be 'the volume of water displaced by any object has the same weight as the object', irrespective of whether the object floats or sinks?the volume of water displaced by a buoyant object has the same weight as the object.
The question clearly stated a half-filled glass, and the finger not touching the glass. So, discounting a hugely fat finger, the glass cannot overflow.
Which will experience an equal and opposite reaction by dint of being hopefully attached to your hand.There will always be gravitational pull.
It would "change" weightSo, if you had some sort of strain gauge on the crane, it would not change as the weight was lowered into the water? What if your 1000 t weight was the same density as water? What if your 1000 t weight was a boat?
Well I ignored that scenario, for the purpose of discussing the effect of a buoyant object.Wrong, how can it not overflow? the bath is full.Ignoring, for now, the scenario of the bath overflowing
Me. I did. And quite explicitly.Who mentioned anything about bouyancy?
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