Because with a ring for volt drop you work on 20 amp load at centre and 12 amp even spread you can use 106 meters of 2.5 mm² cable they normally work out better than radial which still has 20 amp at end and rest even spread. Use 4 mm² on a ring and you can have 179 meters of cable. With 6 mm² 274 meters of cable and still be within the 11.5 volt drop limit.
With industrial premises running 6 mm² in the loft with junction boxes for each sockets dropping down the wall in 2.5 mm² was a way around the problem, with house more likely to use two rings splitting side to side as that reduces the cable required more than up/down split. But it is volt drop due to cable length which is limiting factor, a radial is down to 32 meters of cable at 20 amp and using 2.5 mm² so that would not help at all. (42 meters with 16 amp)
Note:- The 106 meters limit was quoted at a IET lecture, I tried to work this out and even with the full calculation using a correction factor I could not get the figures, so at next IET lecture I asked the question, this was where I was told about the 20 amp centre 12 amp even spread so you calculate at 26 amp when working out the volt drop. After this I wrote an excel program for my phone, when changing phone I re-wrote it in java script so I can now quickly pop in the figures and get results.
However you are the designer, and you could decide that 32 amp would be even spread in the house your building or because of heavy equipment in kitchen there is a 26 amp load in the centre. It is not written in stone or a regulation it is just something designers use as a rule of thumb.
Very like the area is a rule of thumb, if you fit sockets around sides of a 100 m² block, it would need around think the old figure was 82 meters of cable which was the old limit when the volt drop was 4% but with the rules on drilling beams one now uses more cable than the old system so the sq meter rules does not work any more.
Using a loop impedance meter line - neutral one can in theory work out the volt drop, so if incomer is 0.35Ω then maximum any point on the ring is 0.94Ω. However with any standard loop impedance meter you get variations each time you read it, so one could not be 100% that the volt drop is exceeded under 1Ω, and I have never noted anyone to date measuring volt drop.
There has been a problem where solar panels have locked out due to over voltage so the DNO has reduced the voltage to 230 volt nominal rather than the 240 volt which was historical set, this lower voltage has resulted in some fluorescent tubes failing to start, so volt drop is more of a problem today than some 10 years ago, however I would suspect there are very few ring finals which are every tested.