I need to insulate 6.3mm female spade connectors using black heat shrink. I want thickish wall after shrinking. The thinnest part should be 0.6mm and thicker part however thick it is. What size heat shrink should I buy and what shrink ratio? Thanks.
You should obtain Heatshrink that just fits over the spade before being heated. For a thicker final finish put a second sleeve of heat shrink on - you could also use adhesive lined* Heatshrink for the second layer. the reason for a close fit to the spade connector is to ensure the heatshrink shrinks down to to support the wire.
*or use a thin coat of 'Hot Glue' on the outside of the first layer.
If the wider bit is more than double the thinner bit then 2/1 sleeving will not shrink enough, i would opt for 3/1 sleeving to give a wider shrink range,
Even then to get a size to fit over a 6.3mm spade and also shrink down to 0.6 i would have thought unlikely unless you want to pay big bucks.
Outline length of the spade connector = 2.95mm * 2 + 7.34mm * 2 = 20.58mm (the actual length is slightly smaller because of round sides)
Treating the length as the heat shrink circumference: 20.58mm / Pi 3.14 = 6.56mm heat shrink diameter
The nearest shrink size 8mm diameter for 4:1 ratio with unshrunk thickness 0.35mm. Am I correct to think this would give me something close to what I want? A sample 20cm shrink is £1.20. This should be enough for the number of connectors I need to do. Or, I could go with 12mm diameter shrink with 0.4mm thickness.
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