S

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its vast

no speed or time data supplied.

as for the other i need a pencil and paper

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S

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I concur. What gets me is, is this really being supplied to a 12 year old as Maths homework? I admit it doesn't take a lot to get me going these days but how bloody infuriating this is! I mean, imagine the poor kid trying to work it out! Grrrrrrrrrrrrr Teachers!I can't see a way to compute the width without knowing the relative speeds of the boats.

Rant over!

H

It is 1000mts wide.

The boats must always meet at the same point, so if on the first trip that point is "650 metres from

I think its a lesson in the importance of carefully reading and understanding what you read ie not a maths question.

I assert that this is incorrect.The boats must always meet at the same point

That would be true if on each journey the boats departed at the same instant.so if on the first trip that point is "650 metres fromonebank", and on the second trip "they meet 350 mters from theotherbank" then the river is 350+650=1000.

Oh I couldn't agree more. Did you read this:I think its a lesson in the importance of carefully reading and understanding what you read ie not a maths question.

And this:One boat is faster than the other

After arriving at their destinations, each boat remains for ten minutes to change passengers and then sets out on the return journey.

H

All the required detail is in the question, any detail not mentioned is therefore irrelevant and can be disregarded.

So-

The speed difference is constant.

They leave at exactly the same time.

The load is constant.

Wind and tide are irrelevant.

Therefore the boats always meet at the same relative point, 350 from one bank and 650 from the other.

I should have added the word "relative" to my original explanation.

Also "

So what's your excuse?Softus these types of questions cannot be answered by pedants.

Please be so kind as to state which "details" you have "disregarded".All the required detail is in the question, any detail not mentioned is therefore irrelevant and can be disregarded.

And unknown.The speed difference is constant.

Not on the second crossing they don't.They leave at exactly the same time.

All assumptions, but reasonable ones.The load is constant.

Wind and tide are irrelevant.

No. They don't.Therefore the boats always meet at the same relative point, 350 from one bank and 650 from the other.

No need - my relative is bigger than yours, and will duff him up.I should have added the word "relative" to my original explanation.

Your lack of powers of deduction never cease to amaze me holmslaw.Also "After arriving at their destinations, each boat remains for ten minutes" seems irrelevant at first but proves my explanation.

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Teachers seem to have that effect on people!

H

If the wording was to refer to the individual boats it would say "After arriving at its destination".

Therefore, it only after both have "arrived at their destination" that the 10 minutes start, therefore the boats leave at exactly the same time.

The infomation given says that they cross again 350m from the other bank ie bank 'B'. This would have to mean that the boats were travelling at different speeds to what they were on the first crossing, otherwise they would have crossed 650m from bank 'B' travelling at the same speed as the first crossing.

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