I will name and shame the brands tomorrow. With some results too.
Martin
Martin
AFAICS they aren't failing any tests which apply to them per se, only exhibiting properties which have implications for their use in respect of a non-statutory BS which does not apply to them.Yes, something odd is going on here. I find it hard to believe that anyone is manufacturing machines for the UK market whose design is such that they are almost bound to fail the tests. Indeed, I wonder if they would even be allowed to sell such machines in the UK?
That may be true - I just don't know what these 'P'AT rules areAFAICS they aren't failing any tests which apply to them per se, only exhibiting properties which have implications for their use in respect of a non-statutory BS which does not apply to them.
Again, I don't know - the BSI website wants my credit card number before it will tell me anything!AFAICS 1) What does BS EN 60204 say?
I don't think it's transitory (at AC - although it probably would be with DC testing). My understanding/suspicion is that it is persistant at AC, due to the filter capacitor - and we have been told that the (AC) test is undertaken whilst the machine is running.2) If transitory behaviour by a filter is suspected, maybe a better way to measure leakage is to actually measure he current in the cpc while the machine is running?
Again, I don't know - the BSI website wants my credit card number before it will tell me anything!AFAICS 1) What does BS EN 60204 say?
So, as your washing machines have all passed the insulation test at > 20MΩ, is the leakage test necessary?
A basic list of the electrical tests can be found here:
http://www.pat-testing.info/test.htm
The IEE Code of Practice goes through the tests in much greater detail:
http://electrical.theiet.org/books/inspection-test/in-service-inspection.cfm[/QUOTE]
Grizzly has posted the link and as i said the leakage test is not compulsory. Also i note that in some of the replies the figure of .75ma has been raised. for a washing machine which is classed as a stationary or movable appliance its 3.5ma or less. Dont know if that makes a difference when compared to your actuals.

The whole of the 17th Edition is not compulsory. We when inspecting and testing need to show if required in a court of law that we took all reasonable steps to ensure the safety of ourselves and others. Complying with the 17th Edition is one way to do this.Grizzly has posted the link and as i said the leakage test is not compulsory.
Time to try and be helpful now![]()
Are you using a PAT tester that performs a proper leakage test / protective conductor current test, with the appliance powered up to mains voltage, or is it a battery power only tester (for example the Seaward Prime Test 100), that performs a simulated leakage test at something like 40V ac?
This may have a bearing on it (then again it might not).
Another viewpoint: the IEE Code of Practice describes the protective conductor current measurement as "an additional or complementary test to the insulation test, for use if the insulation test cannot be performed or gives suspect results." (section 15.6, page 76).
So, as your washing machines have all passed the insulation test at > 20MΩ, is the leakage test necessary?
To get currents of 3.5mA and 10mA with 230V would require capacitors of at around 0.014 uF and 0.049 uF respectively - values which are in the ballpark of those found as filtering components.
Is this a 'double test' (this time to see if I'm paying attention)?I see that you are testing us John? It appears that you transposed the values to see if we were awakeTo get currents of 3.5mA and 10mA with 230V would require capacitors of at around 0.014 uF and 0.049 uF respectively - values which are in the ballpark of those found as filtering components.![]()
Lower capacitance = higher reactance = higher impedance = lower current. (and the converse)
Ah, right - yes, I'm guilty, but not what I was being accused of (transposition). My decimal point was wrong, and the 10mA one should been approx 0.14 uF, not 0.014 uF. Thanks for noticing this. However, my conclusions remain the same.Your logic is correct but isn't 0.014uF equal to 227,364.4 ohms at 50hz equal to approximately 1mA at 230V? Or am I suffereing from decimalpointitisLower capacitance = higher reactance = higher impedance = lower current. (and the converse)![]()
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