Velocity of the water at the pipe exit will be closely connected to the 'head' of water ie Tank constant water surface height above the pipe exit.

For these purposes, neglecting flows of laminar and turbulent type, and neglecting frictional losses allowing 32 ft /sec² as approximation for 'g'

The velocity at exit will be

**C**x sqrt ( 2g x head) ft / sec where

**C**is the coefficient of velocity ( actual v / theoretical v ) this is an unknown in Breezer's case. and is comprised of all the restraints to the flow.

So theoretical velocity = sqrt ( 2 x 32 x 20 ) = 35.777 ft /sec

This is in an upward direction so 35.777 / 32 = 1.118 sec to lose all upward velocity.

And the height reached using

**v² = u² - 2 g s**where u= initial vel v = final vel s = distance.

Rearranged to

**s = ( u² - v² ) / 2g**leads to s = (35.777² - 0 ) / 64 and this gives an answer of 19.9999 ft ... being the original height.

So theoretically the two plumes reach the same height ie. the tank water surface level.

Obviously friction, type of orifice etc will have an effect and the theoretical height will not be reached... Which pipe generically provides most resistence to flow ? fIIK !!