pool heater

[slup]

You clearly didn't read my post in the way it was intended.

There were three points to it:-

1) Connect it up safely (which he had ignored)
2) It's going to cost a fortune to run (which he had ignored)
3) Pull your head out of your arse and be grateful for the help you have received (which he had completely failed to do)

I certainly wasn't supporting the original poster....

 

[ban-all-sheds]

Not sure what I didn't read properly...

You've had a lot of good advice but have taken some of the negative comments to heart.

but never mind...

 

[slup]

Nice bit of out of context quoting there.

The whole paragraph...

You've had a lot of good advice but have taken some of the negative comments to heart - I think you should climb down off your high horse and thank those people who tried to help.

That reads:-

• You've focused on the negative responses on the thread
  You haven't taken any of the points on board
  Stop getting uppity and listen to the points made

Incidentally, if there was nothing off topic or unreasonable posted, why did the moderator have to delete half a dozen posts?

BAS - you really can be a pain sometimes. I'm not even disagreeing with you and you have managed to find an argument.

 

[ban-all-sheds]

You've focused on the negative responses on the thread.

What negative responses?

I didn't misread you, or quote you out of context to make it look like you said something you hadn't.

There had been no negative responses - which was why I asked what you meant, but it really isn't worth arguing over.

 

[nosedog]

Years later, the forumula's are very useful.

For an indoor hot tub with 100mm of extruded polyethylene foam around
the whole thing except when it is in use, has a total capacity of 700 litres
and 6.4 square meters of surface area to a room with a temperature of
20 degrees. Presuming the water temperature to be 38 makes the
difference to the room 18 degrees

6.4 meters (area) * .4 W/m2 heat loss * 18 degrees = 46.08 watts per hour
or 1.106 kilowatts per day of lost heat to atmosphere outside of bathing
times.

700 litres * .001164 kw = .8148 kilowatts to heat tub one degree
* 18 = 14.67Kilowatts to heat water to temperature

When a normal bath of 120 litres is let out of the tub when it is too cold at 32 degrees, the energy lost over room temperature that was used to heat it, by this formula is 120 * .001164 * 12 degrees over 20 degree room temperature is 1.67 kilowatts lost down the bath plug every bath.

At what thermal efficiency does it make sense to keep a tub warm all
the time and filter the water than to heat up water then tossed away?

 

[IJWS15]

I am amazed that there are people around who do not take the safety of their children, or other's children seriously.

Wonder how the OP would feel if his low cost approach electrocuted a child!