When calculating volt drop at design stage for a ring circuit. Can you halve the result for the 2 legs of the ring?
For example:
2.5 T & E
20 metres
Volt drop = cable length x design current x (mV/A/m) / 1000
Therefore:
Volt drop = 20 x 32 x 18 / 1000 = 11.52V voltdrop.
Do i then divide by 2 to make it 5.76V for each leg
For example:
2.5 T & E
20 metres
Volt drop = cable length x design current x (mV/A/m) / 1000
Therefore:
Volt drop = 20 x 32 x 18 / 1000 = 11.52V voltdrop.
Do i then divide by 2 to make it 5.76V for each leg