Volt drop question...

[Mikey_A]

When calculating volt drop at design stage for a ring circuit. Can you halve the result for the 2 legs of the ring?

For example:

2.5 T & E
20 metres

Volt drop = cable length x design current x (mV/A/m) / 1000

Therefore:

Volt drop = 20 x 32 x 18 / 1000 = 11.52V voltdrop.

Do i then divide by 2 to make it 5.76V for each leg

 

[plugwash]

to get worst case volt drop divide the total length of the ring by 4 before doing the calculation (2 for the fact that the distance to the furthest point is half the lengh of the ring and 2 for the fact there are two legs)

 

[Mikey_A]

to get worst case volt drop divide the total length of the ring by 4 before doing the calculation (2 for the fact that the distance to the furthest point is half the lengh of the ring and 2 for the fact there are two legs)

Which works out at 2.88A

Would that be right then?

 

[plugwash]

volt drop is not measured in amps!

 

[Mikey_A]

volt drop is not measured in amps!

Sorry 2.88V

 

[securespark]

That's better. Don't do it again.

 

[Mikey_A]

That's better. Don't do it again.

I was hoping that thread would disappear off the page...

Thanks for bringing it to the top for all to see

 

[Pensdown]

 

[securespark]

Thanks for bringing it to the top for all to see

Any time, matey!!

 

[Pensdown]

Sad minds think alike