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ok thanks for that. In simple man maths
ok thanks for that. In simple man maths.... if I want to further increase the pump speed from what i've currently got set. I need to buy an external pump capable of more than 700mbar? Do Grundfos ones do larger pumps than this? I presume it'd be best to fit one of those and dial this internal one down instead?
1Kwh = 860 kcal and there are 60 minutes in a hour. (860 = 3,600,000/4186)
Some use a very long winded formula but I've used this for over 60 years since my introduction to SI units.
So, kWh = LPM*60*dT/860 or any variation of this. ( I get mixed up in the lower/upper case of the units but the calc is fine), its actually kgs of water but a litre of water is generally taken a being 1 kg.
It can also be used say to calculate the energy required to heat a "tank" of water + time taken to achieve this with a heating element or coil, for example, energy required to heat a 200L cylinder of water from 10C to 60C = 200*(60-10)/860, 11.628 kWh.
(The long winded calc is, 200*4186*(60-10)/3,600.000.)
A 15kW heating coil or element will take,11.628/15, 0.775 hrs, 46.5 minutes.
ok thanks for that. In simple man maths.... if I want to further increase the pump speed from what i've currently got set. I need to buy an external pump capable of more than 700mbar? Do Grundfos ones do larger pumps than this? I presume it'd be best to fit one of those and dial this internal one down instead?