New Heated Towel Rail blows fuse...

Sponsored Links
Sponsored Links
Its a 300watt PTC energy efficient heating element...
Unless they make a noise, all electric heating elements are as efficient as each other - 100% of the energy they consume is turned into heat.

Your element should be 180-200Ω.
 
How can the filament resistance, L to N, reduce to 0.3Ω if, as I think, L to E is open circuit?
L-E is supposed to be open circuit - it makes towel rails a lot safer.

L-N is 0.3Ω because the element is faulty, and the 800-ish amps it draws is popping the fuse and tripping the circuit breaker.
 
Unless they make a noise, all electric heating elements are as efficient as each other - 100% of the energy they consume is turned into heat.

Your element should be 180-200Ω.

Sorry! Just took that from the eBay description:

•300 watt PTC energy efficient electrical heating element
•Working towel rail temperature 65 C
•Electrical supply 220-240V - 50Hz

Cheers,

R.
 
How can the filament resistance, L to N, reduce to 0.3Ω if, as I think, L to E is open circuit?
L-E is supposed to be open circuit - it makes towel rails a lot safer.
That's what I meant - as it should be with no shorts.

L-N is 0.3Ω because the element is faulty, and the 800-ish amps it draws is popping the fuse and tripping the circuit breaker.
Yes, faulty perhaps but how does the resistance reduce causing overload, let alone by such a huge amount?
 
That's what I meant - as it should be with no shorts.
There is no short to earth - there doesn't have to be for there to be a short from L to N.


Yes, faulty perhaps but how does the resistance reduce causing overload, let alone by such a huge amount?
I don't understand that. What do you mean how does it reduce causing overload?

I'm a little surprised that the first application of power didn't vaporise the fault, but there ya go.
 
That's what I meant - as it should be with no shorts.
There is no short to earth - there doesn't have to be for there to be a short from L to N.
Ah, you mean across the terminals or conductors - not through the filament.
I wasn't thinking of that.

I don't understand that. What do you mean how does it reduce causing overload?
As above.

I'm a little surprised that the first application of power didn't vaporise the fault, but there ya go.
It must be well made.
 
Ah, you mean across the terminals or conductors - not through the filament.
I wasn't thinking of that.
It could be through the element - it could have a short close to the two ends of it.

Wherever it is, it has (so far as we can tell) a resistance of 0.3Ω

And you asked, in effect, was "How does the resistance of 0.3Ω between L & N reduce causing overload, let alone by such a huge amount?".

Sorry - I still have no idea what you mean.


It must be well made.

:mrgreen:
 
And you asked, in effect, was "How does the resistance of 0.3Ω between L & N reduce causing overload, let alone by such a huge amount?".
Sorry - I still have no idea what you mean.
No, the resistance of the filament reducing from whatever it should be to 0.3Ω.

I had in my mind something like an immersion or oven element, not this small element where all the terminals, connections and flex are close together and fixed.

In these items (immersion or oven), if the L to E is open circuit (as it should be), and the L to N should be, say 19Ω, then there is no way any fault in the filament could result in this resistance becoming lower, reducing to 0.3Ω.

I presume that this small probe type element has the filament 'up and back' separated only by insulation so, I now realise, 'anything could happen'.
 

DIYnot Local

Staff member

If you need to find a tradesperson to get your job done, please try our local search below, or if you are doing it yourself you can find suppliers local to you.

Select the supplier or trade you require, enter your location to begin your search.


Are you a trade or supplier? You can create your listing free at DIYnot Local

 
Sponsored Links
Back
Top